GESP C++ 五级真题解析：数字移动 | 极客日志

GESP C++ 五级真题解析：数字移动 | 极客日志

#include <iostream>
using namespace std;
const int N = 100010;
int a[N];
int b[N];
int pos;

int main(){
    int n;
    cin >> n;
    for(int i = 0; i < n; i++){
        cin >> a[i];
    }
    int left = 1, right = 1e6, ans = 1e6;
    while(left <= right){
        int mid = (left + right) / 2;
        bool possible = true;
        pos = 0;
        for(int i = 0; i < n; i++){
            if(a[i] > mid){
                b[pos++] = a[i];
            }
        }
        for(int i = 0; i < pos; i += 2){
            if(b[i] != b[i+1]){
                possible = false;
                break;
            }
        }
        if(possible){
            ans = mid;
            right = mid - 1;
        } else {
            left = mid + 1;
        }
    }
    cout << ans << endl;
    return 0;
}

pos = 0;
for(int i = 0; i < n; i++){
    if(a[i] > mid){
        b[pos++] = a[i];
    }
}

for(int i = 0; i < pos; i += 2){
    if(b[i] != b[i+1]){
        possible = false;
        break;
    }
}

if(possible){
    ans = mid;
    right = mid - 1;
} else {
    left = mid + 1;
}