Python 数据思维:元组基础
元组 (Tuple):不可变有序序列
创建元组
tup = 4, 5, 6
嵌套元组
tup_net = (4, 5, 6), (7, 8)
元组拆包
tup = (4, 5, 6)
a, b, c = tup
# a, b, c 的值分别为 4, 5, 6
嵌套拆包
tup = 4, 5, (6, 7)
a, b, (c, d) = tup
# a, b, c, d 的值分别为 4, 5, 6, 7
遍历拆包
seq = [(1, 2, 3), (4, 5, 6), (7, 8, 9)]
for a, b, c in seq:
print('a={}, b={}, c={}'.format(a, b, c))
输出结果:
a=1, b=2, c=3
a=4, b=5, c=6
=, =, c=

