C++ operator() 重载详解

2.2 累加器实现

class Accumulator {
private:
    int sum;
public:
    Accumulator(int initial = 0) : sum(initial) {}

    int operator()(int value) {
        sum += value;
        return sum;
    }

    void operator()(int value, bool reset) {
        if (reset) sum = 0;
        sum += value;
    }
};

// 调用示例
Accumulator acc(0);
int result1 = acc(5); // sum = 5
int result2 = acc(3); // sum = 8
acc(10, true); // 重置后累加，sum = 10

3. 比较器函数对象

3.1 字符串长度比较器

class StringLengthComparator {
public:
    bool operator()(const std::string& a, const std::string& b) const {
        return a.length() < b.length();
    }
};

// 调用示例
std::vector<std::string> strings = {"apple", "banana", "cherry", "date"};
std::sort(strings.begin(), strings.end(), StringLengthComparator());

3.2 数值比较器

class NumberComparator {
private:
    bool ascending;
public:
    NumberComparator(bool asc = true) : ascending(asc) {}

    bool operator()(int a, int b) const {
        return ascending ? a < b : a > b;
    }
};

// 调用示例
std::vector<int> numbers = {5, 2, 8, 1, 9};
std::sort(numbers.begin(), numbers.end(), NumberComparator(true));   // 升序
std::sort(numbers.begin(), numbers.end(), NumberComparator(false));  // 降序

4. 算法库中的应用

4.1 自定义谓词函数对象

class GreaterThan {
private:
    int threshold;
public:
    GreaterThan(int t) : threshold(t) {}

    bool operator()(int value) const {
        return value > threshold;
    }
};

// 调用示例
std::vector<int> numbers = {1, 5, 3, 8, 2, 9};
int count = std::count_if(numbers.begin(), numbers.end(), GreaterThan(5)); // count = 2 (8, 9)

4.2 变换函数对象

class Square {
public:
    int operator()(int x) const {
        return x * x;
    }
};

class AddConstant {
private:
    int constant;
public:
    AddConstant(int c) : constant(c) {}

    int operator()(int x) const {
        return x + constant;
    }
};

// 调用示例
std::vector<int> input = {1, 2, 3, 4, 5};
std::vector<int> output(input.size());

// 使用 Square
std::transform(input.begin(), input.end(), output.begin(), Square());
// output = {1, 4, 9, 16, 25}

// 使用 AddConstant
std::transform(input.begin(), input.end(), output.begin(), AddConstant(10));
// output = {11, 12, 13, 14, 15}

5. 函数对象容器

5.1 操作器容器

class OperationContainer {
private:
    std::string operation;
public:
    OperationContainer(const std::string& op) : operation(op) {}

    int operator()(int a, int b) const {
        if (operation == "add") return a + b;
        if (operation == "sub") return a - b;
        if (operation == "mul") return a * b;
        if (operation == "div") return b != 0 ? a / b : 0;
        return 0;
    }
};

// 调用示例
OperationContainer addOp("add");
OperationContainer mulOp("mul");
int result1 = addOp(5, 3); // 返回 8
int result2 = mulOp(5, 3); // 返回 15

5.2 条件过滤器

class Filter {
private:
    std::function<bool(int)> condition;
public:
    Filter(std::function<bool(int)> cond) : condition(cond) {}

    std::vector<int> operator()(const std::vector<int>& input) const {
        std::vector<int> result;
        for (int value : input) {
            if (condition(value)) {
                result.push_back(value);
            }
        }
        return result;
    }
};

// 调用示例
std::vector<int> numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

// 过滤偶数
Filter evenFilter([](int x) { return x % 2 == 0; });
auto evenNumbers = evenFilter(numbers); // {2, 4, 6, 8, 10}

// 过滤大于 5 的数
Filter greaterFilter([](int x) { return x > 5; });
auto greaterNumbers = greaterFilter(numbers); // {6, 7, 8, 9, 10}

6. 高级应用场景

6.1 闭包模拟

class Closure {
private:
    int capture_value;
public:
    Closure(int val) : capture_value(val) {}

    int operator()(int x) const {
        return x + capture_value;
    }

    int operator()(int x, int y) const {
        return x * y + capture_value;
    }
};

// 调用示例
Closure closure(10);
int result1 = closure(5); // 返回 15 (5 + 10)
int result2 = closure(3, 4); // 返回 22 (3 * 4 + 10)

6.2 函数组合器

template<typename F, typename G>
class Compose {
private:
    F f;
    G g;
public:
    Compose(F f_func, G g_func) : f(f_func), g(g_func) {}

    template<typename T>
    auto operator()(T x) const -> decltype(f(g(x))) {
        return f(g(x));
    }
};

// 调用示例
auto square = [](int x) { return x * x; };
auto increment = [](int x) { return x + 1; };
Compose<decltype(square), decltype(increment)> compose(square, increment);
int result = compose(5); // 先执行 increment(5) = 6, 再执行 square(6) = 36

7. 性能考虑与最佳实践

7.1 const 修饰符使用

class StatelessFunction {
public:
    // 无状态函数对象应使用 const 修饰
    int operator()(int x) const {
        return x * 2;
    }
};

7.2 引用参数传递

class StringProcessor {
public:
    std::string operator()(const std::string& input) const {
        // 使用 const 引用避免拷贝
        return input + "_processed";
    }
};

8. 总结

• 灵活性：operator() 重载提供了函数对象的灵活性
• 状态保持：函数对象可以维护内部状态
• 算法兼容：与 STL 算法完美配合
• 性能优势：编译时优化，避免函数指针调用开销
• 类型安全：编译时类型检查，避免运行时错误