Java List 根据List中对象的属性值是否相同作为同一组，分割成多个连续的子List

Ne0inhk

21 Mar 2026 — 2 min read

需求：Java List 根据List中对象的属性值是否相同作为同一组，分割成多个连续的子List

package com.suncd.trs.provider.controller; import java.util.ArrayList; import java.util.List; import java.util.function.Function; public class ListGrouping { /** * 将List按照对象属性值是否相同进行分组，分割成多个连续的子List * @param list 原始List * @param keyExtractor 提取对象属性值的函数 * @param <T> List中对象的类型 * @param <K> 属性值的类型 * @return 分割后的子List集合 */ public static <T, K> List<List<T>> groupByProperty(List<T> list, Function<T, K> keyExtractor) { if (list == null || keyExtractor == null) { throw new IllegalArgumentException("List和keyExtractor不能为null"); } List<List<T>> result = new ArrayList<>(); if (list.isEmpty()) { return result; } List<T> currentGroup = new ArrayList<>(); K previousKey = null; for (T item : list) { K currentKey = keyExtractor.apply(item); // 如果是第一个元素，或者当前属性值与前一个不同，则开始新组 if (currentGroup.isEmpty() || !currentKey.equals(previousKey)) { if (!currentGroup.isEmpty()) { result.add(currentGroup); } currentGroup = new ArrayList<>(); } currentGroup.add(item); previousKey = currentKey; } // 添加最后一组 if (!currentGroup.isEmpty()) { result.add(currentGroup); } return result; } // 示例使用 public static void main(String[] args) { // 创建测试数据 List<Person> people = new ArrayList<>(); people.add(new Person("张三", 25)); people.add(new Person("李四", 25)); people.add(new Person("王五", 30)); people.add(new Person("赵六", 27)); people.add(new Person("钱七", 30)); people.add(new Person("孙八", 25)); people.add(new Person("周九", 35)); // 按年龄分组 List<List<Person>> groupedByAge = groupByProperty(people, Person::getAge); System.out.println("按年龄分组:"); for (int i = 0; i < groupedByAge.size(); i++) { System.out.println("组 " + (i + 1) + ": " + groupedByAge.get(i)); } } } class Person { private String name; private int age; public Person(String name, int age) { this.name = name; this.age = age; } public String getName() { return name; } public int getAge() { return age; } @Override public String toString() { return name + "(" + age + ")"; } }

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