// 优化版:一次遍历确定两端极值voidSelectSort(int* arr, int n){
int begin = 0, end = n - 1;
while (begin < end) {
int mini = begin, maxi = begin;
for (int i = begin + 1; i <= end; i++) {
if (arr[i] > arr[maxi]) {
maxi = i;
}
if (arr[i] < arr[mini]) {
mini = i;
}
}
if (begin == maxi) {
maxi = mini;
}
Swap(&arr[mini], &arr[begin]);
Swap(&arr[maxi], &arr[end]);
++begin;
--end;
}
}
int _QuickSort_Pit(int* arr, int left, int right) {
int hole = left;
int key = arr[hole];
while (left < right) {
while (left < right && arr[right] > key) {
--right;
}
arr[hole] = arr[right];
hole = right;
while (left < right && arr[left] < key) {
++left;
}
arr[hole] = arr[left];
hole = left;
}
arr[hole] = key;
return hole;
}
2.3.2.3 Lomuto 前后指针
创建前后指针,从左往右找比基准值小的进行交换,使得小的都排在基准值的左边。
int _QuickSort_Lomuto(int* arr, int left, int right) {
int prev = left, cur = left + 1;
int key = left;
while (cur <= right) {
if (arr[cur] < arr[key] && ++prev != cur) {
Swap(&arr[cur], &arr[prev]);
}
++cur;
}
Swap(&arr[key], &arr[prev]);
return prev;
}
2.3.2.4 非递归版本
非递归版本的快速排序需要借助栈结构来模拟递归调用。
voidQuickSortNonR(int* arr, int left, int right){
ST st;
STInit(&st);
STPush(&st, right);
STPush(&st, left);
while (!STEmpty(&st)) {
int begin = STTop(&st); STPop(&st);
int end = STTop(&st); STPop(&st);
int keyi = begin;
int prev = begin;
int cur = begin + 1;
while (cur <= end) {
if (arr[cur] < arr[keyi] && ++prev != cur)
Swap(&arr[prev], &arr[cur]);
++cur;
}
Swap(&arr[keyi], &arr[prev]);
keyi = prev;
if (keyi + 1 < end) {
STPush(&st, end);
STPush(&st, keyi + 1);
}
if (begin < keyi - 1) {
STPush(&st, keyi - 1);
STPush(&st, begin);
}
}
STDestroy(&st);
}
voidCountSort(int* arr, int n){
int min = arr[0], max = arr[0];
for (int i = 1; i < n; i++) {
if (arr[i] > max) max = arr[i];
if (arr[i] < min) min = arr[i];
}
int range = max - min + 1;
int* count = (int*)malloc(sizeof(int) * range);
memset(count, 0, sizeof(int) * range);
for (int i = 0; i < n; i++) {
count[arr[i] - min]++;
}
int index = 0;
for (int i = 0; i < range; i++) {
while (count[i]--) {
arr[index++] = i + min;
}
}
free(count);
}